1¡¢ÉèISÇúÏߵķ½³ÌΪY=0.415-0.0000185y+0.00005G£¬LMÇúÏߵķ½³ÌΪr=0.00001625y-0.0001M/P¡£Ê½ÖУ¬rΪÀûÂÊ£¬yΪÊÕÈ룬GΪÕþ¸®Ö§³ö£¬PΪ¼Û¸ñˮƽ£¬MΪÃûÒå»õ±ÒÁ¿¡£ÊÔµ¼³ö×ÜÐèÇóÇúÏߣ¬²¢ËµÃ÷ÃûÒå»õ±ÒÁ¿ºÍÕþ¸®Ö§³ö¶Ô×ÜÐèÇóÇúÏßµÄÓ°Ïì¡£ ?XÞÎu?¶k
´ð°¸£ºÁªÁ¢IS·½³ÌÓëLM·½³Ì¼´r=0.415-0.0000185y+0.00005G ±} Êw-?Sf
r=0.00001625y-0.0001M/P t¨¢ØÝÏNŒHg
×ÜÐèÇó·½³ÌΪ£ºy=11942.446+1.4388G+2.8777M/P êd?]a¢ `?
ÃûÒå»õ±ÒÁ¿ºÍÕþ¸®Ö§³öµÄÔö¼Ó»áʹ×ÜÐèÇóÀ©ÕÅ£¬×ÜÐèÇóÇúÏßÏòÓÒÆ½ÒÆ£¬·´Ö®Ôò·´ÊÇ¡£ ?Sï®Å`¯ˆ?
2¡¢Èç¹û×ܹ©¸øÇúÏßΪys=500£¬×ÜÐèÇóÇúÏßΪyd=600-50P œ€3j^3?r
£¨1£©Çó¹©Çó¾ùºâµã£»£¨2£©Èç¹û×ÜÐèÇóÉÏÉý10%£¬ÇóÐµĹ©Çó¾ùºâµã¡£ ™èb[2??r
´ð°¸£º£¨1£© ys=500 yd=600-50P ½âµÃP=2y=500 [®³ÆÜ·/?4
£¨2£©×ÜÐèÇóÉÏÉý10%£¬Ôò×ÜÐèÇóÇúÏßΪyd=660-55P ‹¡žw?øÃs?
ys=500 yd=660-55P ½âµÃP=32/11¡Ö3y=500 HDAå¬äz£Ø
3¡¢É込õÄ×ܹ©¸øº¯ÊýΪy=2350+400P£¬×ÜÐèÇóº¯ÊýΪy=2000+750/P£¬Çó×ܹ©¸øºÍ×ÜÐèÇó¾ùºâʱµÄÊÕÈëºÍ¼Û¸ñˮƽ¡£ ežL³Îb 0Z?
´ð°¸£ºy=2350+400PAS y=2000+750/PAD ½âµÃP=1y=2750 2?û‡’ñåE?
[1]
